Melanie and Steve’s Walker’s Landing Wedding * Amelia Island Wedding Photographers

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  • Chefe - Okay sam so we have (3(5^(n+1)– 1)+3*4*5^(n+1))/4 all divided by 4 but lets just igrone that 1/4 and we’ll bring it in at the end so we have3(5^(n+1) – 1)+3*4*5^(n+1)=3(5^(n+1))-3+12(5^(n+1))=15(5^(n+1))-3So now we take 3 out as a common factor and get:3(5*5^(n+1)-1)But 5*5^(n+1)=5^1*5^(n+1) and when we have to things of the same value raised to different powers we add the powers so we add n+1 and 1 too get n+2so therefore 3(5*5^(n+1)-1)=3(5^(n+2)-1)= 3(5^((n+1)+1)–1)and bringing back in the 1/4 we get like i have above 3(5^((n+1)+1)–1) all divided by 4and so its true for P(n + 1) is true if true for P(n).hopefully that clears it up +7Was this answer helpful?